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categories: deeper and deeper
Vaughan writes
Ok, let me dig myself in deeper by making my example more
complicated. Instead of 1->3, put an arrow from i to j whenever
i <= j <= 2i. Now ever y i is a square coalgebra but no i is a
cubical coalgebra.
There's an arrow from 1 to 2 but none from 1*1 to 1*2. And
when put back in you'll obtain an arrow from 1 to 3.
Even without associativity, if A is a X*X coalgebra then A is
an (X*X)*X coalgebra.